| **Terminal velocity of standard road bike** | filtersweep
*Oct 21, 2003 2:45 PM* | | All this talk of speed has me wondering- what are various terminal velocities at various grades (using no aero equipment).
Let's just put this experiment on sea level...
any ideas? Links, charts, formulas? |
| **No rider? nm** | lotterypick
*Oct 21, 2003 2:51 PM* | | . |
| **Whatever 180 BPM's will yield.** | lotterypick
*Oct 21, 2003 2:52 PM* | | Make it up hill, down hill, whatever. About there I'll pop. |
| **re: Terminal velocity of standard road bike** | sievers11
*Oct 21, 2003 3:27 PM* | | The terminal velocity refers to the maximum speed you can reach when falling if you take wind resistance into account.
So for a specific drag coeficent you should come up with a resonable number, but you would have to free fall from a plane to test.
The other way you can figure out is with a relationship to a specific angle of decent, assuming zero friction.
I would have to look up the formulas, but it is almost irrelvant because there are too many variables...9 degree grade, semi aero tuck with average cut clothing and 32 spoke wheels...how far to reach terminal speed.
Who cares. |
| **Here's some numbers** | Kerry Irons
*Oct 21, 2003 3:47 PM* | | 6% grade = 33 mph/53 kph
8% grade = 39 mph/62 kph
10% grade = 44 mph/70 kph
12% grade = 48 mph/77 kph
20% grade = 62 mph/100 kph
These numbers are to the nearest mph, and reflect staying in your standard road riding position. A tight tuck will up these numbers considerably, but I don't have the aero factors for the tuck position. I'm guessing that a 6% grade in a tight tuck is good for well over 40 mph.
The formula is: calories per hour = [V*W(.0053 + %G/100) + .0083(V^3)]*7.2
Where V = speed in mph, W = rider+bike weight in lb., and G is the grade. You just solve the formula for velocity with zero calories by inserting a negative grade. |
| **re: Terminal velocity of standard road bike** | Chainstay
*Oct 21, 2003 6:14 PM* | | Isn't freefall terminal velocity about 110 mph? Any sky divers out there? Add the bike and you would slow down to maybe 90 mph. I keep a chute in my jersey pocket just in case. |
| **124** | Steve_0
*Oct 22, 2003 6:13 AM* | | tv is roughly 124. Of course, thats freefall. With the bike scenario you also need to account for grades and rolling resistance
I agree with the other poster; too many variables for a realistic estimation.
(fwiw- the weight of the bike will not affect the tv during freefall). |
| **African or European ? (nm)** | LO McDuff
*Oct 22, 2003 10:37 AM* | | |
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